DC Cable Voltage Drop Calculator

Solar DC string and battery cable voltage drop with the 1% / 2% design limits used for PV array and battery circuits.

Inputs

Use Isc × 1.25 for PV strings

PV cable in sunlight commonly reaches 70–90 °C

Formula

  • ΔV = 2 × ρ_T × L × I / A (DC always uses the go-and-return path)
  • ρ_T = ρ₂₀ (1 + α (T − 20))
  • Energy loss ratio = ΔV / V

DC circuits in PV systems carry current continuously at peak sun, so even a small percentage drop compounds into a real annual yield loss. Industry practice limits array DC drop to 1% and battery-to-inverter drop to 2%, because low-voltage battery circuits carry very high current where every milliohm matters.

Step-by-step calculation

  1. Resistivity at temperature

    ρ₂₀(1 + α(T − 20))

    0.02058 Ω·mm²/m

  2. Voltage drop

    2 × ρ × L × I / A

    4.939 V

  3. Percentage

    ΔV / V × 100

    0.823%

  4. Required area

    2ρLI / (target% × V)

    3.29 mm²

Worked example

  • String of 12 A over 40 m of 4 mm² copper at 70 °C, 600 V DC.
  • ρ₇₀ = 0.02058 Ω·mm²/m; ΔV = 2 × 0.02058 × 40 × 12 / 4 = 4.94 V = 0.82% — within the 1% target.

Assumptions

  • Double-insulated PV cable rated 1.5 kV DC with a 90–120 °C conductor rating.
  • Current is taken as the continuous design current, not the instantaneous peak.

Tips

  • Keep string cable runs short by placing combiner boxes near the array.
  • For battery banks, use short, equal-length cables to keep parallel strings balanced.

Warnings

  • A 48 V battery bank carrying 200 A loses 2% in only a few metres — always oversize battery cables.
  • PV DC cables must be UV-resistant and rated for the full open-circuit voltage at the lowest site temperature.

Standards & references

  • IEC 62548 (PV array design)
  • IEC 60364-7-712
  • IS 16221

Frequently asked questions

What is the maximum voltage drop for solar DC cables?

1% from array to inverter and 2% from battery to inverter are the accepted design targets; codes allow up to 3% but yield suffers.

Why is DC drop calculated with a factor of 2?

Because current flows out along the positive conductor and back along the negative, so the total resistive path is twice the route length.

Should I use Isc or Imp for string cables?

Size the conductor for 1.25 × Isc for safety, but calculate voltage drop and yield loss at Imp, the actual operating current.

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