Simply supported centre load
Given: P = 10 kN, L = 4 m, E = 200 GPa, I = 8×10⁻⁶ m⁴
Working: δ = 10000 × 4³ / (48 × 200×10⁹ × 8×10⁻⁶)
Maximum deflection ≈ 8.33 mm.
Learn common beam deflection formulas for simply supported and cantilever beams, including point-load and UDL cases, with worked examples and a live calculator.
Beam deflection is the displacement of a beam from its unloaded position. Classical elastic formulas depend strongly on span length, loading, Young's modulus and the second moment of area.
Other load/support cases use different coefficients. For example, a cantilever with an end point load uses δmax = P × L³ / (3EI), while a simply supported beam under full-span UDL uses 5wL⁴ / (384EI).
Simply supported beam with a point load at midspan.
Simply supported beam, centre point load
| Symbol | Meaning | Typical SI unit |
|---|---|---|
| δmax | Maximum elastic deflection | m or mm |
| P | Point load | N |
| L | Beam span | m |
| E | Young's modulus | Pa |
| I | Second moment of area | m⁴ |
Given: P = 10 kN, L = 4 m, E = 200 GPa, I = 8×10⁻⁶ m⁴
Working: δ = 10000 × 4³ / (48 × 200×10⁹ × 8×10⁻⁶)
Maximum deflection ≈ 8.33 mm.
Given: Same beam and load, but span doubles
Working: Point-load deflection varies with L³
Doubling span increases this elastic deflection by about 8 times.
The quick calculator above demonstrates the governing equation. Open the related engineering tool for broader inputs, outputs and calculation context where available.
For a simply supported beam with a point load at midspan, δmax = PL³/(48EI).
For a cantilever with a point load at the free end, δmax = PL³/(3EI).
Many beam deflection equations contain L³ or L⁴, so span length has a strong nonlinear effect.
No. Strength, stability, local buckling, connections and code-specific checks must also be satisfied.
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