Rectangular section
Given: b = 100 mm, h = 200 mm
Working: I = 100 × 200³ / 12
I = 66,666,666.7 mm⁴.
Learn area moment of inertia formulas for rectangles and circles, the parallel-axis theorem and how to calculate section inertia for beam bending and deflection.
In beam and structural calculations, the area moment of inertia (second moment of area) describes how cross-sectional area is distributed about an axis. A larger I generally means greater bending stiffness for the same material.
For a solid circle about a centroidal diameter, I = πd⁴/64. To shift a centroidal inertia to a parallel axis, use I = Ic + A d².
Centroidal x-axis formula I = bh³/12.
Rectangle about centroidal axis parallel to width
| Symbol | Meaning | Typical SI unit |
|---|---|---|
| I | Area moment of inertia | mm⁴ or m⁴ |
| b | Rectangle width | mm or m |
| h | Rectangle depth perpendicular to the axis | mm or m |
| A | Cross-sectional area for parallel-axis theorem | mm² or m² |
Given: b = 100 mm, h = 200 mm
Working: I = 100 × 200³ / 12
I = 66,666,666.7 mm⁴.
Given: Rotate the same 100 × 200 mm rectangle by 90°
Working: I now uses h = 100 mm and b = 200 mm
The inertia about that axis becomes much smaller because depth is cubed.
The quick calculator above demonstrates the governing equation. Open the related engineering tool for broader inputs, outputs and calculation context where available.
About its centroidal axis parallel to width b, the area moment of inertia is I = bh³/12.
About a centroidal diameter, I = πd⁴/64.
It shifts a centroidal second moment of area to a parallel axis using I = Ic + Ad².
No. Area moment of inertia is a geometric section property used in bending and deflection; mass moment of inertia describes rotational resistance of mass.
Continue with another problem-first engineering equation.