Maximum stress example
Given: M = 5 kN·m, c = 50 mm, I = 8×10⁶ mm⁴
Working: σ = (5,000,000 N·mm × 50 mm) / 8,000,000 mm⁴
σ = 31.25 MPa.
Learn the bending stress formula σ = My/I, its variables, units and assumptions, with worked examples and a live maximum bending-stress calculator.
The elastic flexure formula relates normal bending stress to bending moment, distance from the neutral axis and the section's second moment of area.
For maximum elastic bending stress, y is usually the distance c from the neutral axis to the extreme fibre. The relationship assumes classical linear-elastic beam behaviour within its applicable range.
Uses σ = Mc/I with moment in kN·m and section properties in mm units.
Elastic maximum flexural stress
| Symbol | Meaning | Typical SI unit |
|---|---|---|
| σ | Bending stress | MPa or Pa |
| M | Bending moment at the section | N·m or N·mm |
| y | Distance from neutral axis | m or mm |
| I | Second moment of area | m⁴ or mm⁴ |
Given: M = 5 kN·m, c = 50 mm, I = 8×10⁶ mm⁴
Working: σ = (5,000,000 N·mm × 50 mm) / 8,000,000 mm⁴
σ = 31.25 MPa.
Given: Same M and c, but I doubles
Working: Stress is inversely proportional to I
Bending stress is reduced by half.
The quick calculator above demonstrates the governing equation. Open the related engineering tool for broader inputs, outputs and calculation context where available.
For classical elastic beam bending, σ = My/I. Maximum stress uses the extreme-fibre distance c.
In SI engineering work it is commonly reported in pascals or megapascals (MPa).
Section modulus Z = I/c, so maximum bending stress can also be written σmax = M/Z.
No. Stress and deflection are separate checks even though both depend on section geometry.
Continue with another problem-first engineering equation.